<?php
/*************************************数据库连接开始*************************************/
$content=mysql_connect($host,$user,$pass)or die("请认真的查看用户名与密码是不是正确");
mysql_select_db($db);
/**************************************数据库连接结束***********************************/
if($_GET['ID']){
$id=$_GET['ID'];
$select_news="select * from symbols where ID='$id'";
mysql_query("set names utf8");
$query_news=mysql_query($select_news);
if (mysql_num_rows($query_news)>0) {
echo " <table border=1 width=800 height=100 align=center>";
while ($row=mysql_fetch_array($query_news)){
echo " <tr>";
echo " <td>标题: </td>";
echo " <td>".$row[1]." </td>";
echo " </tr>";
echo " <tr>";
echo " <td>标题: </td>";
echo " <td>".$row[2]." </td>";
echo " </tr>";
echo " <tr>";
echo " <td>标题: </td>";
echo " <td>".$row[3]." </td>";
echo " </tr>";
echo " <tr>";
echo " <td>标题: </td>";
echo " <td>".$row[4]." </td>";
echo " </tr>";
echo " <tr>";
echo " <td>标题: </td>";
echo " <td>".$row[5]." </td>";
echo " </tr>";
}
echo " </table>";
}
}
?>
以上程序是我写的如何从mysql数据库中把数据读出来并且显示,我现在想把它写成当我单击“更新按钮”按钮的时候能够完成表单里的数据更新,我写很很长时间老报错,大家能帮助我写下吗?谢谢了!
posted on 2008-09-08 15:10
王永平 阅读(579)
评论(1) 编辑 收藏 引用 网摘